write a program in java to print first 100 even number with serial number

 In this problem we have to print first 100 even numbers along with the serial numbers. There will be 50 even numbers from 1-100.

Approach :

Take your first step by opening IntelliJ to write the code. We will use for loop with if statement to tackle this problem. We will initialize a variable to keep the count of serial number.

Java    JavaScript

Code :

package com.StepTowardsCoding;

public class even {

    public static void main(String[] args) {
        int count = 1;
        for (int i = 1; i <= 100; i++) {
            if (i % 2 == 0) {
                System.out.println(count+". " + i);
                count+=1;
            }
        }
    }
}

Output :

1. 2
2. 4
3. 6
4. 8
5. 10
6. 12
7. 14
8. 16
9. 18
10. 20
11. 22
12. 24
13. 26
14. 28
15. 30
16. 32
17. 34
18. 36
19. 38
20. 40
21. 42
22. 44
23. 46
24. 48
25. 50
26. 52
27. 54
28. 56
29. 58
30. 60
31. 62
32. 64
33. 66
34. 68
35. 70
36. 72
37. 74
38. 76
39. 78
40. 80
41. 82
42. 84
43. 86
44. 88
45. 90
46. 92
47. 94
48. 96
49. 98
50. 100

Explanation :

I had initialized a variable count of type integer which will keep the count of Serial Number. After that I had created a for loop from 1 to 100 with +1 increment, 'i' is the variable used in the for loop. The value of 'i' is even or not is checked in the if statement by using the condition i%2 == 0. Modulus(%) is used to return a remainder. When 'i' is divided by 2 and the remainder is 0, which means 'i' is divisible by 2 and is even. The 'i' is printed along with count and count get increased by 1.

When the condition is false, it do nothing and starts the next execution.